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1252554403 is a prime number
BaseRepresentation
bin100101010101000…
…0111011010100011
310020021220100121211
41022222013122203
510031123220103
6324142330551
743016352052
oct11252073243
93207810554
101252554403
11593041731
122ab589a57
1316c665469
14bc4d0399
1574e6c36d
hex4aa876a3

1252554403 has 2 divisors, whose sum is σ = 1252554404. Its totient is φ = 1252554402.

The previous prime is 1252554343. The next prime is 1252554431. The reversal of 1252554403 is 3044552521.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1252554403 is a prime.

It is not a weakly prime, because it can be changed into another prime (1252554703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626277201 + 626277202.

It is an arithmetic number, because the mean of its divisors is an integer number (626277202).

Almost surely, 21252554403 is an apocalyptic number.

1252554403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1252554403 is an equidigital number, since it uses as much as digits as its factorization.

1252554403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24000, while the sum is 31.

The square root of 1252554403 is about 35391.4453364086. The cubic root of 1252554403 is about 1077.9506183471.

The spelling of 1252554403 in words is "one billion, two hundred fifty-two million, five hundred fifty-four thousand, four hundred three".