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125300431600121 is a prime number
BaseRepresentation
bin11100011111010111000111…
…101101110011100111111001
3121102122121022111221202011102
4130133113013231303213321
5112410410240442200441
61122254120145141145
735251441334335241
oct3437270755634771
9542577274852142
10125300431600121
1136a19684076588
121207809102a7b5
1354bba1a87650b
1422d2804dc6b21
15e7454238c69b
hex71f5c7b739f9

125300431600121 has 2 divisors, whose sum is σ = 125300431600122. Its totient is φ = 125300431600120.

The previous prime is 125300431600079. The next prime is 125300431600147. The reversal of 125300431600121 is 121006134003521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94913480946025 + 30386950654096 = 9742355^2 + 5512436^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125300431600121 is a prime.

It is not a weakly prime, because it can be changed into another prime (125300431605121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62650215800060 + 62650215800061.

It is an arithmetic number, because the mean of its divisors is an integer number (62650215800061).

Almost surely, 2125300431600121 is an apocalyptic number.

It is an amenable number.

125300431600121 is a deficient number, since it is larger than the sum of its proper divisors (1).

125300431600121 is an equidigital number, since it uses as much as digits as its factorization.

125300431600121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 125300431600121 its reverse (121006134003521), we get a palindrome (246306565603642).

The spelling of 125300431600121 in words is "one hundred twenty-five trillion, three hundred billion, four hundred thirty-one million, six hundred thousand, one hundred twenty-one".