Base | Representation |
---|---|
bin | 1011011001010110010100… |
… | …0000110011111100011111 |
3 | 1122100212102012200110202111 |
4 | 2312111211000303330133 |
5 | 3120243133231022030 |
6 | 42352131031334451 |
7 | 2432161625230624 |
oct | 266254500637437 |
9 | 48325365613674 |
10 | 12530114314015 |
11 | 3aa0a9a964121 |
12 | 14a4505b21427 |
13 | 6cb77a7b857c |
14 | 3146644c634b |
15 | 16ae0c70d62a |
hex | b6565033f1f |
12530114314015 has 4 divisors (see below), whose sum is σ = 15036137176824. Its totient is φ = 10024091451208.
The previous prime is 12530114314007. The next prime is 12530114314043. The reversal of 12530114314015 is 51041341103521.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12530114314015 - 23 = 12530114314007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1253011431397 + ... + 1253011431406.
It is an arithmetic number, because the mean of its divisors is an integer number (3759034294206).
Almost surely, 212530114314015 is an apocalyptic number.
12530114314015 is a deficient number, since it is larger than the sum of its proper divisors (2506022862809).
12530114314015 is an equidigital number, since it uses as much as digits as its factorization.
12530114314015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2506022862808.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 12530114314015 its reverse (51041341103521), we get a palindrome (63571455417536).
The spelling of 12530114314015 in words is "twelve trillion, five hundred thirty billion, one hundred fourteen million, three hundred fourteen thousand, fifteen".
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