Base | Representation |
---|---|
bin | 11100011111011100110001… |
… | …111101110000011001011001 |
3 | 121102200012000001220102111121 |
4 | 130133130301331300121121 |
5 | 112411010212314232101 |
6 | 1122301003211525241 |
7 | 35252045052454201 |
oct | 3437346175603131 |
9 | 542605001812447 |
10 | 125306509133401 |
11 | 36a21212743262 |
12 | 120792a8459821 |
13 | 54bc478a1a95b |
14 | 22d2c20219401 |
15 | e7479abdd0a1 |
hex | 71f731f70659 |
125306509133401 has 2 divisors, whose sum is σ = 125306509133402. Its totient is φ = 125306509133400.
The previous prime is 125306509133317. The next prime is 125306509133527. The reversal of 125306509133401 is 104331905603521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 65549280255001 + 59757228878400 = 8096251^2 + 7730280^2 .
It is a cyclic number.
It is not a de Polignac number, because 125306509133401 - 213 = 125306509125209 is a prime.
It is not a weakly prime, because it can be changed into another prime (125306509233401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62653254566700 + 62653254566701.
It is an arithmetic number, because the mean of its divisors is an integer number (62653254566701).
Almost surely, 2125306509133401 is an apocalyptic number.
It is an amenable number.
125306509133401 is a deficient number, since it is larger than the sum of its proper divisors (1).
125306509133401 is an equidigital number, since it uses as much as digits as its factorization.
125306509133401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 291600, while the sum is 43.
The spelling of 125306509133401 in words is "one hundred twenty-five trillion, three hundred six billion, five hundred nine million, one hundred thirty-three thousand, four hundred one".
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