Base | Representation |
---|---|
bin | 1110111100000… |
… | …01110010010011 |
3 | 22201210111221122 |
4 | 13132001302103 |
5 | 224034442042 |
6 | 20233512455 |
7 | 3051064352 |
oct | 736016223 |
9 | 281714848 |
10 | 125312147 |
11 | 6480a964 |
12 | 35b7272b |
13 | 1cc66acc |
14 | 128dd999 |
15 | b0047d2 |
hex | 7781c93 |
125312147 has 2 divisors, whose sum is σ = 125312148. Its totient is φ = 125312146.
The previous prime is 125312123. The next prime is 125312153. The reversal of 125312147 is 741213521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 125312147 - 28 = 125311891 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (125312347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62656073 + 62656074.
It is an arithmetic number, because the mean of its divisors is an integer number (62656074).
Almost surely, 2125312147 is an apocalyptic number.
125312147 is a deficient number, since it is larger than the sum of its proper divisors (1).
125312147 is an equidigital number, since it uses as much as digits as its factorization.
125312147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1680, while the sum is 26.
The square root of 125312147 is about 11194.2908216644. The cubic root of 125312147 is about 500.4158500416.
Adding to 125312147 its reverse (741213521), we get a palindrome (866525668).
The spelling of 125312147 in words is "one hundred twenty-five million, three hundred twelve thousand, one hundred forty-seven".
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