Base | Representation |
---|---|
bin | 11100011111100011000000… |
… | …111001100100000101000001 |
3 | 121102200211021111222120101111 |
4 | 130133203000321210011001 |
5 | 112411112414222043203 |
6 | 1122304031302203321 |
7 | 35252402653222264 |
oct | 3437430071440501 |
9 | 542624244876344 |
10 | 125313202143553 |
11 | 36a24037779906 |
12 | 1207a655a23541 |
13 | 54bcca45493a8 |
14 | 22d32970a2cdb |
15 | e74a3d5b726d |
hex | 71f8c0e64141 |
125313202143553 has 2 divisors, whose sum is σ = 125313202143554. Its totient is φ = 125313202143552.
The previous prime is 125313202143533. The next prime is 125313202143629. The reversal of 125313202143553 is 355341202313521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114145655106609 + 11167547036944 = 10683897^2 + 3341788^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125313202143553 is a prime.
It is not a weakly prime, because it can be changed into another prime (125313202143533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62656601071776 + 62656601071777.
It is an arithmetic number, because the mean of its divisors is an integer number (62656601071777).
Almost surely, 2125313202143553 is an apocalyptic number.
It is an amenable number.
125313202143553 is a deficient number, since it is larger than the sum of its proper divisors (1).
125313202143553 is an equidigital number, since it uses as much as digits as its factorization.
125313202143553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 40.
The spelling of 125313202143553 in words is "one hundred twenty-five trillion, three hundred thirteen billion, two hundred two million, one hundred forty-three thousand, five hundred fifty-three".
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