1253143305044 has 6 divisors (see below), whose sum is σ = 2193000783834. Its totient is φ = 626571652520.

The previous prime is 1253143304989. The next prime is 1253143305049. The reversal of 1253143305044 is 4405033413521.

It can be written as a sum of positive squares in only one way, i.e., 1192927052944 + 60216252100 = 1092212^2 + 245390^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1253143304995 and 1253143305013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1253143305049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156642913127 + ... + 156642913134.

It is an arithmetic number, because the mean of its divisors is an integer number (365500130639).

Almost surely, 2^{1253143305044} is an apocalyptic number.

It is an amenable number.

1253143305044 is a deficient number, since it is larger than the sum of its proper divisors (939857478790).

1253143305044 is a wasteful number, since it uses less digits than its factorization.

1253143305044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 313285826265 (or 313285826263 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 1253143305044 its reverse (4405033413521), we get a palindrome (5658176718565).

The spelling of 1253143305044 in words is "one trillion, two hundred fifty-three billion, one hundred forty-three million, three hundred five thousand, forty-four".