Base | Representation |
---|---|
bin | 111010010110101011… |
… | …0111111101100000110 |
3 | 102222110102101100100222 |
4 | 1310231112333230012 |
5 | 4023121123214332 |
6 | 133322520304342 |
7 | 12024265246442 |
oct | 1645526775406 |
9 | 388412340328 |
10 | 125315054342 |
11 | 49167099115 |
12 | 203539120b2 |
13 | ba813b503a |
14 | 60cb1b9822 |
15 | 33d68e1712 |
hex | 1d2d5bfb06 |
125315054342 has 4 divisors (see below), whose sum is σ = 187972581516. Its totient is φ = 62657527170.
The previous prime is 125315054321. The next prime is 125315054383. The reversal of 125315054342 is 243450513521.
125315054342 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31328763584 + ... + 31328763587.
It is an arithmetic number, because the mean of its divisors is an integer number (46993145379).
Almost surely, 2125315054342 is an apocalyptic number.
125315054342 is a deficient number, since it is larger than the sum of its proper divisors (62657527174).
125315054342 is an equidigital number, since it uses as much as digits as its factorization.
125315054342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62657527173.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 125315054342 its reverse (243450513521), we get a palindrome (368765567863).
The spelling of 125315054342 in words is "one hundred twenty-five billion, three hundred fifteen million, fifty-four thousand, three hundred forty-two".
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