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125317433 is a prime number
BaseRepresentation
bin1110111100000…
…11000100111001
322201210210012102
413132003010321
5224040124213
620233553145
73051115643
oct736030471
9281723172
10125317433
116481392a
1235b757b5
131cc69337
1412901893
15b006158
hex7783139

125317433 has 2 divisors, whose sum is σ = 125317434. Its totient is φ = 125317432.

The previous prime is 125317399. The next prime is 125317441. The reversal of 125317433 is 334713521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96983104 + 28334329 = 9848^2 + 5323^2 .

It is a cyclic number.

It is not a de Polignac number, because 125317433 - 28 = 125317177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125317396 and 125317405.

It is not a weakly prime, because it can be changed into another prime (125317333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62658716 + 62658717.

It is an arithmetic number, because the mean of its divisors is an integer number (62658717).

Almost surely, 2125317433 is an apocalyptic number.

It is an amenable number.

125317433 is a deficient number, since it is larger than the sum of its proper divisors (1).

125317433 is an equidigital number, since it uses as much as digits as its factorization.

125317433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7560, while the sum is 29.

The square root of 125317433 is about 11194.5269216702. The cubic root of 125317433 is about 500.4228862336.

The spelling of 125317433 in words is "one hundred twenty-five million, three hundred seventeen thousand, four hundred thirty-three".