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12531753030257 is a prime number
BaseRepresentation
bin1011011001011100011010…
…1100000001001001110001
31122101000122102012212211122
42312113012230001021301
53120310012233432012
642353001410552025
72432250344131166
oct266270654011161
948330572185748
1012531753030257
113aa176097996a
1214a48a2898615
136cb97c158756
1431477bdb806d
1516aea6508e72
hexb65c6b01271

12531753030257 has 2 divisors, whose sum is σ = 12531753030258. Its totient is φ = 12531753030256.

The previous prime is 12531753030239. The next prime is 12531753030317. The reversal of 12531753030257 is 75203035713521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6292828119601 + 6238924910656 = 2508551^2 + 2497784^2 .

It is a cyclic number.

It is not a de Polignac number, because 12531753030257 - 214 = 12531753013873 is a prime.

It is a super-2 number, since 2×125317530302572 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12531753030227) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6265876515128 + 6265876515129.

It is an arithmetic number, because the mean of its divisors is an integer number (6265876515129).

Almost surely, 212531753030257 is an apocalyptic number.

It is an amenable number.

12531753030257 is a deficient number, since it is larger than the sum of its proper divisors (1).

12531753030257 is an equidigital number, since it uses as much as digits as its factorization.

12531753030257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 661500, while the sum is 44.

Adding to 12531753030257 its reverse (75203035713521), we get a palindrome (87734788743778).

The spelling of 12531753030257 in words is "twelve trillion, five hundred thirty-one billion, seven hundred fifty-three million, thirty thousand, two hundred fifty-seven".