125325041404303 has 32 divisors (see below), whose sum is σ = 136762156339200. Its totient is φ = 114156393044736.

The previous prime is 125325041404217. The next prime is 125325041404331. The reversal of 125325041404303 is 303404140523521.

It is a cyclic number.

It is not a de Polignac number, because 125325041404303 - 2¹⁷ = 125325041273231 is a prime.

It is a super-2 number, since 2×125325041404303² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125325041404393) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 239384538 + ... + 239907496.

It is an arithmetic number, because the mean of its divisors is an integer number (4273817385600).

Almost surely, 2^{125325041404303} is an apocalyptic number.

125325041404303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

125325041404303 is a deficient number, since it is larger than the sum of its proper divisors (11437114934897).

125325041404303 is a wasteful number, since it uses less digits than its factorization.

125325041404303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 523911.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 125325041404303 its reverse (303404140523521), we get a palindrome (428729181927824).

The spelling of 125325041404303 in words is "one hundred twenty-five trillion, three hundred twenty-five billion, forty-one million, four hundred four thousand, three hundred three".