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12532505833201 is a prime number
BaseRepresentation
bin1011011001011111001110…
…0011101110111011110001
31122101002120212202020100011
42312113303203232323301
53120313032443130301
642353204222054521
72432305114633024
oct266276343567361
948332525666304
1012532505833201
113aa2007903962
1214a4a72a1a441
136cba6c0c4c93
1431480dd791bb
1516aeec65ba51
hexb65f38eeef1

12532505833201 has 2 divisors, whose sum is σ = 12532505833202. Its totient is φ = 12532505833200.

The previous prime is 12532505833193. The next prime is 12532505833261. The reversal of 12532505833201 is 10233850523521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12487636426225 + 44869406976 = 3533785^2 + 211824^2 .

It is a cyclic number.

It is not a de Polignac number, because 12532505833201 - 23 = 12532505833193 is a prime.

It is a super-3 number, since 3×125325058332013 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12532505833261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6266252916600 + 6266252916601.

It is an arithmetic number, because the mean of its divisors is an integer number (6266252916601).

Almost surely, 212532505833201 is an apocalyptic number.

It is an amenable number.

12532505833201 is a deficient number, since it is larger than the sum of its proper divisors (1).

12532505833201 is an equidigital number, since it uses as much as digits as its factorization.

12532505833201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 40.

The spelling of 12532505833201 in words is "twelve trillion, five hundred thirty-two billion, five hundred five million, eight hundred thirty-three thousand, two hundred one".