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1253340145483 is a prime number
BaseRepresentation
bin10010001111010000111…
…001001110011101001011
311102211002102121020211021
4102033100321032131023
5131013320034123413
62355435421013311
7156356636313166
oct22172071163513
94384072536737
101253340145483
114435a1923958
12182aa50b4237
139126035487a
144493a6c4add
152290791318d
hex123d0e4e74b

1253340145483 has 2 divisors, whose sum is σ = 1253340145484. Its totient is φ = 1253340145482.

The previous prime is 1253340145451. The next prime is 1253340145559. The reversal of 1253340145483 is 3845410433521.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1253340145483 - 25 = 1253340145451 is a prime.

It is not a weakly prime, because it can be changed into another prime (1253340145433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626670072741 + 626670072742.

It is an arithmetic number, because the mean of its divisors is an integer number (626670072742).

Almost surely, 21253340145483 is an apocalyptic number.

1253340145483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1253340145483 is an equidigital number, since it uses as much as digits as its factorization.

1253340145483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 691200, while the sum is 43.

The spelling of 1253340145483 in words is "one trillion, two hundred fifty-three billion, three hundred forty million, one hundred forty-five thousand, four hundred eighty-three".