Base | Representation |
---|---|
bin | 10010001111010001001… |
… | …001000101111111101011 |
3 | 11102211002201102120210022 |
4 | 102033101021011333223 |
5 | 131013322120231011 |
6 | 2355440050111055 |
7 | 156360016546352 |
oct | 22172111057753 |
9 | 4384081376708 |
10 | 1253344305131 |
11 | 4435a4205086 |
12 | 182aa657b48b |
13 | 9126117ccb9 |
14 | 4493b088999 |
15 | 22907e858db |
hex | 123d1245feb |
1253344305131 has 2 divisors, whose sum is σ = 1253344305132. Its totient is φ = 1253344305130.
The previous prime is 1253344305127. The next prime is 1253344305181. The reversal of 1253344305131 is 1315034433521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1253344305131 - 22 = 1253344305127 is a prime.
It is a super-2 number, since 2×12533443051312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1253344305091 and 1253344305100.
It is not a weakly prime, because it can be changed into another prime (1253344305181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626672152565 + 626672152566.
It is an arithmetic number, because the mean of its divisors is an integer number (626672152566).
Almost surely, 21253344305131 is an apocalyptic number.
1253344305131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1253344305131 is an equidigital number, since it uses as much as digits as its factorization.
1253344305131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 1253344305131 its reverse (1315034433521), we get a palindrome (2568378738652).
The spelling of 1253344305131 in words is "one trillion, two hundred fifty-three billion, three hundred forty-four million, three hundred five thousand, one hundred thirty-one".
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