1253371288151 has 4 divisors (see below), whose sum is σ = 1257649006152. Its totient is φ = 1249093570152.

The previous prime is 1253371288121. The next prime is 1253371288189. The reversal of 1253371288151 is 1518821733521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1253371288151 is a prime.

It is a super-2 number, since 2×1253371288151² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1253371288096 and 1253371288105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1253371288121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2138858561 + ... + 2138859146.

It is an arithmetic number, because the mean of its divisors is an integer number (314412251538).

Almost surely, 2^{1253371288151} is an apocalyptic number.

1253371288151 is a deficient number, since it is larger than the sum of its proper divisors (4277718001).

1253371288151 is an equidigital number, since it uses as much as digits as its factorization.

1253371288151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4277718000.

The product of its digits is 403200, while the sum is 47.

The spelling of 1253371288151 in words is "one trillion, two hundred fifty-three billion, three hundred seventy-one million, two hundred eighty-eight thousand, one hundred fifty-one".