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12534052489537 is a prime number
BaseRepresentation
bin1011011001100100111110…
…1111110000100101000001
31122101020120200001111222011
42312121033233300211001
53120324214414131122
642354021512212521
72432361335201125
oct266311757604501
948336520044864
1012534052489537
113aa2730960737
1214a522499a141
136cbc57671747
14314919545585
1516b08d320377
hexb664fbf0941

12534052489537 has 2 divisors, whose sum is σ = 12534052489538. Its totient is φ = 12534052489536.

The previous prime is 12534052489529. The next prime is 12534052489559. The reversal of 12534052489537 is 73598425043521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9314697896001 + 3219354593536 = 3051999^2 + 1794256^2 .

It is a cyclic number.

It is not a de Polignac number, because 12534052489537 - 23 = 12534052489529 is a prime.

It is not a weakly prime, because it can be changed into another prime (12534052489507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267026244768 + 6267026244769.

It is an arithmetic number, because the mean of its divisors is an integer number (6267026244769).

Almost surely, 212534052489537 is an apocalyptic number.

It is an amenable number.

12534052489537 is a deficient number, since it is larger than the sum of its proper divisors (1).

12534052489537 is an equidigital number, since it uses as much as digits as its factorization.

12534052489537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288000, while the sum is 58.

The spelling of 12534052489537 in words is "twelve trillion, five hundred thirty-four billion, fifty-two million, four hundred eighty-nine thousand, five hundred thirty-seven".