Base | Representation |
---|---|
bin | 1011011001100100111110… |
… | …1111111000011011111001 |
3 | 1122101020120200010011010011 |
4 | 2312121033233320123321 |
5 | 3120324214421143341 |
6 | 42354021513021521 |
7 | 2432361335364013 |
oct | 266311757703371 |
9 | 48336520104104 |
10 | 12534052521721 |
11 | 3aa2730982935 |
12 | 14a52249b48a1 |
13 | 6cbc576832a3 |
14 | 3149195531b3 |
15 | 16b08d329b81 |
hex | b664fbf86f9 |
12534052521721 has 2 divisors, whose sum is σ = 12534052521722. Its totient is φ = 12534052521720.
The previous prime is 12534052521707. The next prime is 12534052521857. The reversal of 12534052521721 is 12712525043521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10080879001600 + 2453173520121 = 3175040^2 + 1566261^2 .
It is a cyclic number.
It is not a de Polignac number, because 12534052521721 - 213 = 12534052513529 is a prime.
It is not a weakly prime, because it can be changed into another prime (12534052522721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267026260860 + 6267026260861.
It is an arithmetic number, because the mean of its divisors is an integer number (6267026260861).
Almost surely, 212534052521721 is an apocalyptic number.
It is an amenable number.
12534052521721 is a deficient number, since it is larger than the sum of its proper divisors (1).
12534052521721 is an equidigital number, since it uses as much as digits as its factorization.
12534052521721 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 168000, while the sum is 40.
The spelling of 12534052521721 in words is "twelve trillion, five hundred thirty-four billion, fifty-two million, five hundred twenty-one thousand, seven hundred twenty-one".
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