Base | Representation |
---|---|
bin | 10111010110010010… |
… | …01010110110110001 |
3 | 1012100120210011120212 |
4 | 23223021022312301 |
5 | 201132423442423 |
6 | 5431500113505 |
7 | 622425415121 |
oct | 135311126661 |
9 | 35316704525 |
10 | 12534984113 |
11 | 5352743103 |
12 | 2519b35895 |
13 | 1249c48382 |
14 | 86cabcc81 |
15 | 4d56e9578 |
hex | 2eb24adb1 |
12534984113 has 2 divisors, whose sum is σ = 12534984114. Its totient is φ = 12534984112.
The previous prime is 12534984101. The next prime is 12534984127. The reversal of 12534984113 is 31148943521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8991401329 + 3543582784 = 94823^2 + 59528^2 .
It is a cyclic number.
It is not a de Polignac number, because 12534984113 - 24 = 12534984097 is a prime.
It is not a weakly prime, because it can be changed into another prime (12534984173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267492056 + 6267492057.
It is an arithmetic number, because the mean of its divisors is an integer number (6267492057).
Almost surely, 212534984113 is an apocalyptic number.
It is an amenable number.
12534984113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12534984113 is an equidigital number, since it uses as much as digits as its factorization.
12534984113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 41.
The spelling of 12534984113 in words is "twelve billion, five hundred thirty-four million, nine hundred eighty-four thousand, one hundred thirteen".
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