Base | Representation |
---|---|
bin | 10111010110010101… |
… | …01101110100100001 |
3 | 1012100121112202122012 |
4 | 23223022231310201 |
5 | 201133024430343 |
6 | 5431512522305 |
7 | 622432023665 |
oct | 135312556441 |
9 | 35317482565 |
10 | 12535389473 |
11 | 535299a712 |
12 | 251a0b0395 |
13 | 124a05aa29 |
14 | 86cb868a5 |
15 | 4d5779718 |
hex | 2eb2add21 |
12535389473 has 2 divisors, whose sum is σ = 12535389474. Its totient is φ = 12535389472.
The previous prime is 12535389463. The next prime is 12535389491. The reversal of 12535389473 is 37498353521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11714165824 + 821223649 = 108232^2 + 28657^2 .
It is an emirp because it is prime and its reverse (37498353521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12535389473 - 212 = 12535385377 is a prime.
It is not a weakly prime, because it can be changed into another prime (12535389463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6267694736 + 6267694737.
It is an arithmetic number, because the mean of its divisors is an integer number (6267694737).
Almost surely, 212535389473 is an apocalyptic number.
It is an amenable number.
12535389473 is a deficient number, since it is larger than the sum of its proper divisors (1).
12535389473 is an equidigital number, since it uses as much as digits as its factorization.
12535389473 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2721600, while the sum is 50.
The spelling of 12535389473 in words is "twelve billion, five hundred thirty-five million, three hundred eighty-nine thousand, four hundred seventy-three".
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