1253540031 has 4 divisors (see below), whose sum is σ = 1671386712. Its totient is φ = 835693352.

The previous prime is 1253540023. The next prime is 1253540053. The reversal of 1253540031 is 1300453521.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1300453521 = 3 ⋅433484507.

It is a cyclic number.

It is not a de Polignac number, because 1253540031 - 2³ = 1253540023 is a prime.

It is a super-2 number, since 2×1253540031² = 3142725218638961922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1253539983 and 1253540010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1253540011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208923336 + ... + 208923341.

It is an arithmetic number, because the mean of its divisors is an integer number (417846678).

Almost surely, 2^1253540031 is an apocalyptic number.

1253540031 is a deficient number, since it is larger than the sum of its proper divisors (417846681).

1253540031 is an equidigital number, since it uses as much as digits as its factorization.

1253540031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 417846680.

The product of its (nonzero) digits is 1800, while the sum is 24.

The square root of 1253540031 is about 35405.3672626058. The cubic root of 1253540031 is about 1078.2332886382.

Adding to 1253540031 its reverse (1300453521), we get a palindrome (2553993552).

The spelling of 1253540031 in words is "one billion, two hundred fifty-three million, five hundred forty thousand, thirty-one".