Base | Representation |
---|---|
bin | 10111010110101100… |
… | …10110100110110101 |
3 | 1012100211021202100000 |
4 | 23223112112212311 |
5 | 201134320040432 |
6 | 5432102141513 |
7 | 622466661000 |
oct | 135326264665 |
9 | 35324252300 |
10 | 12538440117 |
11 | 5354693705 |
12 | 251b121899 |
13 | 124a888448 |
14 | 86d33c537 |
15 | 4d5b7d57c |
hex | 2eb5969b5 |
12538440117 has 96 divisors (see below), whose sum is σ = 23194080000. Its totient is φ = 6742600704.
The previous prime is 12538440067. The next prime is 12538440121. The reversal of 12538440117 is 71104483521.
12538440117 is a `hidden beast` number, since 1 + 2 + 538 + 4 + 4 + 0 + 117 = 666.
It is not a de Polignac number, because 12538440117 - 27 = 12538439989 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12538440217) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1412509 + ... + 1421357.
It is an arithmetic number, because the mean of its divisors is an integer number (241605000).
Almost surely, 212538440117 is an apocalyptic number.
12538440117 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
It is an amenable number.
12538440117 is a deficient number, since it is larger than the sum of its proper divisors (10655639883).
12538440117 is an frugal number, since it uses more digits than its factorization.
12538440117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8902 (or 8876 counting only the distinct ones).
The product of its (nonzero) digits is 26880, while the sum is 36.
The spelling of 12538440117 in words is "twelve billion, five hundred thirty-eight million, four hundred forty thousand, one hundred seventeen".
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