Base | Representation |
---|---|
bin | 11100100000101001100010… |
… | …110100100111001001001001 |
3 | 121102222001202100022202120001 |
4 | 130200221202310213021021 |
5 | 112413333013344322114 |
6 | 1122402514121403001 |
7 | 35261023440451546 |
oct | 3440514264471111 |
9 | 542861670282501 |
10 | 125388933198409 |
11 | 36a531699a9251 |
12 | 12091270039461 |
13 | 54c7183115b5a |
14 | 22d6bdccb9bcd |
15 | e769c1dd8374 |
hex | 720a62d27249 |
125388933198409 has 2 divisors, whose sum is σ = 125388933198410. Its totient is φ = 125388933198408.
The previous prime is 125388933198371. The next prime is 125388933198437. The reversal of 125388933198409 is 904891339883521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125388933198400 + 9 = 11197720^2 + 3^2 .
It is a cyclic number.
It is not a de Polignac number, because 125388933198409 - 223 = 125388924809801 is a prime.
It is not a weakly prime, because it can be changed into another prime (125388933198509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62694466599204 + 62694466599205.
It is an arithmetic number, because the mean of its divisors is an integer number (62694466599205).
Almost surely, 2125388933198409 is an apocalyptic number.
It is an amenable number.
125388933198409 is a deficient number, since it is larger than the sum of its proper divisors (1).
125388933198409 is an equidigital number, since it uses as much as digits as its factorization.
125388933198409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403107840, while the sum is 73.
The spelling of 125388933198409 in words is "one hundred twenty-five trillion, three hundred eighty-eight billion, nine hundred thirty-three million, one hundred ninety-eight thousand, four hundred nine".
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