Base | Representation |
---|---|
bin | 10111010110110001… |
… | …01110010011100001 |
3 | 1012100212110022200012 |
4 | 23223120232103201 |
5 | 201134444431343 |
6 | 5432123334305 |
7 | 622505156351 |
oct | 135330562341 |
9 | 35325408605 |
10 | 12539061473 |
11 | 5354a78524 |
12 | 251b381395 |
13 | 124aa45203 |
14 | 86d460b61 |
15 | 4d5c52718 |
hex | 2eb62e4e1 |
12539061473 has 2 divisors, whose sum is σ = 12539061474. Its totient is φ = 12539061472.
The previous prime is 12539061439. The next prime is 12539061481. The reversal of 12539061473 is 37416093521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10423797409 + 2115264064 = 102097^2 + 45992^2 .
It is an emirp because it is prime and its reverse (37416093521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12539061473 - 210 = 12539060449 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12539061473.
It is not a weakly prime, because it can be changed into another prime (12539061413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6269530736 + 6269530737.
It is an arithmetic number, because the mean of its divisors is an integer number (6269530737).
Almost surely, 212539061473 is an apocalyptic number.
It is an amenable number.
12539061473 is a deficient number, since it is larger than the sum of its proper divisors (1).
12539061473 is an equidigital number, since it uses as much as digits as its factorization.
12539061473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 41.
The spelling of 12539061473 in words is "twelve billion, five hundred thirty-nine million, sixty-one thousand, four hundred seventy-three".
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