Search a number
-
+
12540253405201 = 30821940686179
BaseRepresentation
bin1011011001111100000101…
…0110011000000000010001
31122101211120211011200010021
42312133001112120000101
53120424414332431301
642400525103303441
72433001112126344
oct266370126300021
948354524150107
1012540253405201
113aa532313a425
1214a64755aab81
136cc705255502
14314d46cd445b
1516b3028e38a1
hexb67c1598011

12540253405201 has 4 divisors (see below), whose sum is σ = 12540294399600. Its totient is φ = 12540212410804.

The previous prime is 12540253405129. The next prime is 12540253405237. The reversal of 12540253405201 is 10250435204521.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12540253405201 - 29 = 12540253404689 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12540257405201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20034871 + ... + 20651308.

It is an arithmetic number, because the mean of its divisors is an integer number (3135073599900).

Almost surely, 212540253405201 is an apocalyptic number.

It is an amenable number.

12540253405201 is a deficient number, since it is larger than the sum of its proper divisors (40994399).

12540253405201 is an equidigital number, since it uses as much as digits as its factorization.

12540253405201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40994398.

The product of its (nonzero) digits is 48000, while the sum is 34.

Adding to 12540253405201 its reverse (10250435204521), we get a palindrome (22790688609722).

The spelling of 12540253405201 in words is "twelve trillion, five hundred forty billion, two hundred fifty-three million, four hundred five thousand, two hundred one".

Divisors: 1 308219 40686179 12540253405201