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12540375403 = 112930493643
BaseRepresentation
bin10111010110111011…
…01111000101101011
31012100221221002001021
423223131233011223
5201140314003103
65432211433311
7622522301143
oct135335570553
935327832037
1012540375403
115355795716
12251b8b5837
13124b0b529a
1486d6c3923
154d5e11bbd
hex2eb76f16b

12540375403 has 8 divisors (see below), whose sum is σ = 12559046000. Its totient is φ = 12521720448.

The previous prime is 12540375343. The next prime is 12540375413. The reversal of 12540375403 is 30457304521.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12540375403 - 225 = 12506820971 is a prime.

It is a super-2 number, since 2×125403754032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12540375413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3440500 + ... + 3444142.

It is an arithmetic number, because the mean of its divisors is an integer number (1569880750).

Almost surely, 212540375403 is an apocalyptic number.

12540375403 is a deficient number, since it is larger than the sum of its proper divisors (18670597).

12540375403 is a wasteful number, since it uses less digits than its factorization.

12540375403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7821.

The product of its (nonzero) digits is 50400, while the sum is 34.

Adding to 12540375403 its reverse (30457304521), we get a palindrome (42997679924).

The spelling of 12540375403 in words is "twelve billion, five hundred forty million, three hundred seventy-five thousand, four hundred three".

Divisors: 1 1129 3049 3643 3442321 4112947 11107507 12540375403