12540375343 has 2 divisors, whose sum is σ = 12540375344. Its totient is φ = 12540375342.

The previous prime is 12540375311. The next prime is 12540375413. The reversal of 12540375343 is 34357304521.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12540375343 - 2⁵ = 12540375311 is a prime.

It is a super-2 number, since 2×12540375343² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12540375643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6270187671 + 6270187672.

It is an arithmetic number, because the mean of its divisors is an integer number (6270187672).

Almost surely, 2^12540375343 is an apocalyptic number.

12540375343 is a deficient number, since it is larger than the sum of its proper divisors (1).

12540375343 is an equidigital number, since it uses as much as digits as its factorization.

12540375343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 37.

Adding to 12540375343 its reverse (34357304521), we get a palindrome (46897679864).

The spelling of 12540375343 in words is "twelve billion, five hundred forty million, three hundred seventy-five thousand, three hundred forty-three".