Search a number
-
+
125405511313 is a prime number
BaseRepresentation
bin111010011001011000…
…0000011111010010001
3102222200201121001000011
41310302300003322101
54023312302330223
6133335511154521
712026444154415
oct1646260037221
9388621531004
10125405511313
1149203161845
122037a075a41
13ba97066c84
1460d9204d45
1533de80d80d
hex1d32c03e91

125405511313 has 2 divisors, whose sum is σ = 125405511314. Its totient is φ = 125405511312.

The previous prime is 125405511281. The next prime is 125405511347. The reversal of 125405511313 is 313115504521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106208854609 + 19196656704 = 325897^2 + 138552^2 .

It is a cyclic number.

It is not a de Polignac number, because 125405511313 - 25 = 125405511281 is a prime.

It is not a weakly prime, because it can be changed into another prime (125405511373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62702755656 + 62702755657.

It is an arithmetic number, because the mean of its divisors is an integer number (62702755657).

Almost surely, 2125405511313 is an apocalyptic number.

It is an amenable number.

125405511313 is a deficient number, since it is larger than the sum of its proper divisors (1).

125405511313 is an equidigital number, since it uses as much as digits as its factorization.

125405511313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9000, while the sum is 31.

The spelling of 125405511313 in words is "one hundred twenty-five billion, four hundred five million, five hundred eleven thousand, three hundred thirteen".