Base | Representation |
---|---|
bin | 11100100000111110100101… |
… | …010011011100101000001110 |
3 | 121110001020001200210122100122 |
4 | 130200332211103130220032 |
5 | 112414220244443231132 |
6 | 1122421131500224542 |
7 | 35262453314230151 |
oct | 3440764523345016 |
9 | 543036050718318 |
10 | 125411523414542 |
11 | 36a6180154aa62 |
12 | 1209571553b152 |
13 | 54c9343319351 |
14 | 22d7d431b7c98 |
15 | e77395250912 |
hex | 720fa54dca0e |
125411523414542 has 4 divisors (see below), whose sum is σ = 188117285121816. Its totient is φ = 62705761707270.
The previous prime is 125411523414539. The next prime is 125411523414637. The reversal of 125411523414542 is 245414325114521.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 125411523414493 and 125411523414502.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31352880853634 + ... + 31352880853637.
It is an arithmetic number, because the mean of its divisors is an integer number (47029321280454).
Almost surely, 2125411523414542 is an apocalyptic number.
125411523414542 is a deficient number, since it is larger than the sum of its proper divisors (62705761707274).
125411523414542 is an equidigital number, since it uses as much as digits as its factorization.
125411523414542 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62705761707273.
The product of its digits is 768000, while the sum is 44.
The spelling of 125411523414542 in words is "one hundred twenty-five trillion, four hundred eleven billion, five hundred twenty-three million, four hundred fourteen thousand, five hundred forty-two".
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