Base | Representation |
---|---|
bin | 10111010111000010… |
… | …00011011111011011 |
3 | 1012101000120021110111 |
4 | 23223201003133123 |
5 | 201141024323103 |
6 | 5432242225151 |
7 | 622532553451 |
oct | 135341033733 |
9 | 35330507414 |
10 | 12541245403 |
11 | 535622a325 |
12 | 25200551b7 |
13 | 124b32b28b |
14 | 86d86c9d1 |
15 | 4d603486d |
hex | 2eb8437db |
12541245403 has 2 divisors, whose sum is σ = 12541245404. Its totient is φ = 12541245402.
The previous prime is 12541245383. The next prime is 12541245413. The reversal of 12541245403 is 30454214521.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12541245403 - 213 = 12541237211 is a prime.
It is not a weakly prime, because it can be changed into another prime (12541245413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6270622701 + 6270622702.
It is an arithmetic number, because the mean of its divisors is an integer number (6270622702).
Almost surely, 212541245403 is an apocalyptic number.
12541245403 is a deficient number, since it is larger than the sum of its proper divisors (1).
12541245403 is an equidigital number, since it uses as much as digits as its factorization.
12541245403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 12541245403 its reverse (30454214521), we get a palindrome (42995459924).
The spelling of 12541245403 in words is "twelve billion, five hundred forty-one million, two hundred forty-five thousand, four hundred three".
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