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125436212943553 is a prime number
BaseRepresentation
bin11100100001010101100100…
…111010100001101011000001
3121110010120210100111200001001
4130201111210322201223001
5112420121331003143203
61122440333430412001
735264316201611251
oct3441254472415301
9543116710450031
10125436212943553
1136a71221100596
121209a465b01001
1354cb779429a05
1422d9206223961
15e77d3ca4691d
hex721564ea1ac1

125436212943553 has 2 divisors, whose sum is σ = 125436212943554. Its totient is φ = 125436212943552.

The previous prime is 125436212943523. The next prime is 125436212943589. The reversal of 125436212943553 is 355349212634521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 119881739698704 + 5554473244849 = 10949052^2 + 2356793^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125436212943553 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125436212943494 and 125436212943503.

It is not a weakly prime, because it can be changed into another prime (125436212943523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62718106471776 + 62718106471777.

It is an arithmetic number, because the mean of its divisors is an integer number (62718106471777).

Almost surely, 2125436212943553 is an apocalyptic number.

It is an amenable number.

125436212943553 is a deficient number, since it is larger than the sum of its proper divisors (1).

125436212943553 is an equidigital number, since it uses as much as digits as its factorization.

125436212943553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23328000, while the sum is 55.

The spelling of 125436212943553 in words is "one hundred twenty-five trillion, four hundred thirty-six billion, two hundred twelve million, nine hundred forty-three thousand, five hundred fifty-three".