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12544125353 is a prime number
BaseRepresentation
bin10111010111011000…
…00010100110101001
31012101012222121000022
423223230002212221
5201142244002403
65432424050225
7622566210014
oct135354024651
935335877008
1012544125353
115357917051
122521003975
13124bac90a6
1486ddbc37b
154d6402d38
hex2ebb029a9

12544125353 has 2 divisors, whose sum is σ = 12544125354. Its totient is φ = 12544125352.

The previous prime is 12544125331. The next prime is 12544125409. The reversal of 12544125353 is 35352144521.

12544125353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6881863849 + 5662261504 = 82957^2 + 75248^2 .

It is a cyclic number.

It is not a de Polignac number, because 12544125353 - 216 = 12544059817 is a prime.

It is not a weakly prime, because it can be changed into another prime (12544128353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6272062676 + 6272062677.

It is an arithmetic number, because the mean of its divisors is an integer number (6272062677).

Almost surely, 212544125353 is an apocalyptic number.

It is an amenable number.

12544125353 is a deficient number, since it is larger than the sum of its proper divisors (1).

12544125353 is an equidigital number, since it uses as much as digits as its factorization.

12544125353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72000, while the sum is 35.

Adding to 12544125353 its reverse (35352144521), we get a palindrome (47896269874).

The spelling of 12544125353 in words is "twelve billion, five hundred forty-four million, one hundred twenty-five thousand, three hundred fifty-three".