125442240202053 has 48 divisors (see below), whose sum is σ = 184710354716160. Its totient is φ = 82020123247392.

The previous prime is 125442240202043. The next prime is 125442240202061. The reversal of 125442240202053 is 350202042244521.

125442240202053 is a `hidden beast` number, since 1 + 2 + 5 + 4 + 42 + 2 + 402 + 0 + 205 + 3 = 666.

It is not a de Polignac number, because 125442240202053 - 2⁶ = 125442240201989 is a prime.

It is a super-3 number, since 3×125442240202053³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125442240201999 and 125442240202017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125442240202043) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1720164850 + ... + 1720237772.

It is an arithmetic number, because the mean of its divisors is an integer number (3848132389920).

Almost surely, 2^{125442240202053} is an apocalyptic number.

It is an amenable number.

125442240202053 is a deficient number, since it is larger than the sum of its proper divisors (59268114514107).

125442240202053 is a wasteful number, since it uses less digits than its factorization.

125442240202053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 89718 (or 89715 counting only the distinct ones).

The product of its (nonzero) digits is 153600, while the sum is 36.

Adding to 125442240202053 its reverse (350202042244521), we get a palindrome (475644282446574).

The spelling of 125442240202053 in words is "one hundred twenty-five trillion, four hundred forty-two billion, two hundred forty million, two hundred two thousand, fifty-three".