Base | Representation |
---|---|
bin | 10111011000000010… |
… | …10111101111110111 |
3 | 1012101121111200021201 |
4 | 23230001113233313 |
5 | 201200211420413 |
6 | 5433143553331 |
7 | 622664556106 |
oct | 135401275767 |
9 | 35347450251 |
10 | 12549716983 |
11 | 535aa96131 |
12 | 2522a5b847 |
13 | 125000624b |
14 | 870a3603d |
15 | 4d6b599dd |
hex | 2ec057bf7 |
12549716983 has 4 divisors (see below), whose sum is σ = 12708574240. Its totient is φ = 12390859728.
The previous prime is 12549716957. The next prime is 12549717001. The reversal of 12549716983 is 38961794521.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12549716983 - 25 = 12549716951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12549716483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79428510 + ... + 79428667.
It is an arithmetic number, because the mean of its divisors is an integer number (3177143560).
Almost surely, 212549716983 is an apocalyptic number.
12549716983 is a deficient number, since it is larger than the sum of its proper divisors (158857257).
12549716983 is an equidigital number, since it uses as much as digits as its factorization.
12549716983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 158857256.
The product of its digits is 3265920, while the sum is 55.
The spelling of 12549716983 in words is "twelve billion, five hundred forty-nine million, seven hundred sixteen thousand, nine hundred eighty-three".
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