Base | Representation |
---|---|
bin | 100101011010001… |
… | …0000100001011011 |
3 | 10020110220102201211 |
4 | 1022310100201123 |
5 | 10032313310042 |
6 | 324315323551 |
7 | 43051064356 |
oct | 11264204133 |
9 | 3213812654 |
10 | 1255213147 |
11 | 594598241 |
12 | 2b04505b7 |
13 | 170086696 |
14 | bc9c329d |
15 | 752e5017 |
hex | 4ad1085b |
1255213147 has 2 divisors, whose sum is σ = 1255213148. Its totient is φ = 1255213146.
The previous prime is 1255213121. The next prime is 1255213159. The reversal of 1255213147 is 7413125521.
It is a strong prime.
It is an emirp because it is prime and its reverse (7413125521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1255213147 - 215 = 1255180379 is a prime.
It is not a weakly prime, because it can be changed into another prime (1255213117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627606573 + 627606574.
It is an arithmetic number, because the mean of its divisors is an integer number (627606574).
Almost surely, 21255213147 is an apocalyptic number.
1255213147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1255213147 is an equidigital number, since it uses as much as digits as its factorization.
1255213147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8400, while the sum is 31.
The square root of 1255213147 is about 35428.9873832149. The cubic root of 1255213147 is about 1078.7127859832.
Adding to 1255213147 its reverse (7413125521), we get a palindrome (8668338668).
The spelling of 1255213147 in words is "one billion, two hundred fifty-five million, two hundred thirteen thousand, one hundred forty-seven".
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