Base | Representation |
---|---|
bin | 1011011010101100000110… |
… | …1101011100001010100101 |
3 | 1122110001212012202200200211 |
4 | 2312223001231130022211 |
5 | 3121132314423302240 |
6 | 42410500201135421 |
7 | 2433635422312003 |
oct | 266530155341245 |
9 | 48401765680624 |
10 | 12553144353445 |
11 | 3aaa838800663 |
12 | 14a8a7278a571 |
13 | 7009aab64637 |
14 | 31580ad93a73 |
15 | 16b8094a3bea |
hex | b6ac1b5c2a5 |
12553144353445 has 32 divisors (see below), whose sum is σ = 16323807595392. Its totient is φ = 9230271977472.
The previous prime is 12553144353427. The next prime is 12553144353457. The reversal of 12553144353445 is 54435344135521.
12553144353445 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 12553144353445 - 233 = 12544554418853 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19727169 + ... + 20353561.
It is an arithmetic number, because the mean of its divisors is an integer number (510118987356).
Almost surely, 212553144353445 is an apocalyptic number.
It is an amenable number.
12553144353445 is a deficient number, since it is larger than the sum of its proper divisors (3770663241947).
12553144353445 is a wasteful number, since it uses less digits than its factorization.
12553144353445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 631941.
The product of its digits is 8640000, while the sum is 49.
Adding to 12553144353445 its reverse (54435344135521), we get a palindrome (66988488488966).
The spelling of 12553144353445 in words is "twelve trillion, five hundred fifty-three billion, one hundred forty-four million, three hundred fifty-three thousand, four hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.094 sec. • engine limits •