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125532203514241 is a prime number
BaseRepresentation
bin11100100010101110111110…
…011001011111100110000001
3121110110202120002200220020211
4130202232332121133212001
5112423204423044423431
61122552410445434121
735304255012161416
oct3442567631374601
9543422502626224
10125532203514241
1136aa89aa2a2047
12120b4b94b6b941
135507836395b74
1422ddb1099810d
15e7a5a9c972b1
hex722bbe65f981

125532203514241 has 2 divisors, whose sum is σ = 125532203514242. Its totient is φ = 125532203514240.

The previous prime is 125532203514233. The next prime is 125532203514283. The reversal of 125532203514241 is 142415302235521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91440851625841 + 34091351888400 = 9562471^2 + 5838780^2 .

It is a cyclic number.

It is not a de Polignac number, because 125532203514241 - 23 = 125532203514233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 125532203514194 and 125532203514203.

It is not a weakly prime, because it can be changed into another prime (125532203514041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62766101757120 + 62766101757121.

It is an arithmetic number, because the mean of its divisors is an integer number (62766101757121).

Almost surely, 2125532203514241 is an apocalyptic number.

It is an amenable number.

125532203514241 is a deficient number, since it is larger than the sum of its proper divisors (1).

125532203514241 is an equidigital number, since it uses as much as digits as its factorization.

125532203514241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 125532203514241 its reverse (142415302235521), we get a palindrome (267947505749762).

The spelling of 125532203514241 in words is "one hundred twenty-five trillion, five hundred thirty-two billion, two hundred three million, five hundred fourteen thousand, two hundred forty-one".