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1255403340097 is a prime number
BaseRepresentation
bin10010010001001011110…
…111101100000101000001
311110000102012212101202121
4102101023313230011001
5131032031223340342
62400420242244241
7156462031215634
oct22211367540501
94400365771677
101255403340097
11444460503575
12183380056681
13914cb926c9a
1444a9470dc1b
15229c8b0a067
hex1244bdec141

1255403340097 has 2 divisors, whose sum is σ = 1255403340098. Its totient is φ = 1255403340096.

The previous prime is 1255403340077. The next prime is 1255403340223. The reversal of 1255403340097 is 7900433045521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1190366099521 + 65037240576 = 1091039^2 + 255024^2 .

It is an emirp because it is prime and its reverse (7900433045521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1255403340097 - 27 = 1255403339969 is a prime.

It is not a weakly prime, because it can be changed into another prime (1255403340077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627701670048 + 627701670049.

It is an arithmetic number, because the mean of its divisors is an integer number (627701670049).

Almost surely, 21255403340097 is an apocalyptic number.

It is an amenable number.

1255403340097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1255403340097 is an equidigital number, since it uses as much as digits as its factorization.

1255403340097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 453600, while the sum is 43.

The spelling of 1255403340097 in words is "one trillion, two hundred fifty-five billion, four hundred three million, three hundred forty thousand, ninety-seven".