Base | Representation |
---|---|
bin | 11100100010111000001111… |
… | …010101101011100111100011 |
3 | 121110111201020101102001120101 |
4 | 130202320033111223213203 |
5 | 112423340311224412003 |
6 | 1123001133531323231 |
7 | 35305056354636445 |
oct | 3442701725534743 |
9 | 543451211361511 |
10 | 125542151404003 |
11 | 37002144654944 |
12 | 120b6ab05b0517 |
13 | 5508760339579 |
14 | 23003b5c34495 |
15 | e7a98d2b011d |
hex | 722e0f56b9e3 |
125542151404003 has 2 divisors, whose sum is σ = 125542151404004. Its totient is φ = 125542151404002.
The previous prime is 125542151403989. The next prime is 125542151404037. The reversal of 125542151404003 is 300404151245521.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125542151404003 is a prime.
It is a super-2 number, since 2×1255421514040032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (125542151404063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62771075702001 + 62771075702002.
It is an arithmetic number, because the mean of its divisors is an integer number (62771075702002).
Almost surely, 2125542151404003 is an apocalyptic number.
125542151404003 is a deficient number, since it is larger than the sum of its proper divisors (1).
125542151404003 is an equidigital number, since it uses as much as digits as its factorization.
125542151404003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96000, while the sum is 37.
The spelling of 125542151404003 in words is "one hundred twenty-five trillion, five hundred forty-two billion, one hundred fifty-one million, four hundred four thousand, three".
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