Base | Representation |
---|---|
bin | 1011011010110011001101… |
… | …0100000110010100101000 |
3 | 1122110020210001011110200110 |
4 | 2312230303110012110220 |
5 | 3121200220340004000 |
6 | 42411413244334320 |
7 | 2434033564562256 |
oct | 266546324062450 |
9 | 48406701143613 |
10 | 12555050313000 |
11 | 4000626657248 |
12 | 14a9304b443a0 |
13 | 700c229a3960 |
14 | 31594c16d5d6 |
15 | 16b8bb98c850 |
hex | b6b33506528 |
12555050313000 has 256 divisors, whose sum is σ = 43545778698240. Its totient is φ = 2990780928000.
The previous prime is 12555050312993. The next prime is 12555050313049. The reversal of 12555050313000 is 31305055521.
It is a super-2 number, since 2×125550503130002 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3983329 + ... + 6401328.
It is an arithmetic number, because the mean of its divisors is an integer number (170100698040).
Almost surely, 212555050313000 is an apocalyptic number.
12555050313000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12555050313000 is an abundant number, since it is smaller than the sum of its proper divisors (30990728385240).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12555050313000 is a wasteful number, since it uses less digits than its factorization.
12555050313000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10384725 (or 10384711 counting only the distinct ones).
The product of its (nonzero) digits is 11250, while the sum is 30.
Adding to 12555050313000 its reverse (31305055521), we get a palindrome (12586355368521).
The spelling of 12555050313000 in words is "twelve trillion, five hundred fifty-five billion, fifty million, three hundred thirteen thousand".
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