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125552022331 is a prime number
BaseRepresentation
bin111010011101101111…
…0111101001100111011
3110000001221021120100011
41310323132331030323
54024112304203311
6133402223322351
712033203403301
oct1647336751473
9400057246304
10125552022331
114927893072a
12203bb1503b7
13babb513a98
146110862271
1533ec5ee321
hex1d3b7bd33b

125552022331 has 2 divisors, whose sum is σ = 125552022332. Its totient is φ = 125552022330.

The previous prime is 125552022313. The next prime is 125552022359. The reversal of 125552022331 is 133220255521.

Together with previous prime (125552022313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 125552022331 - 213 = 125552014139 is a prime.

It is a super-4 number, since 4×1255520223314 (a number of 45 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 125552022293 and 125552022302.

It is not a weakly prime, because it can be changed into another prime (125552022311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62776011165 + 62776011166.

It is an arithmetic number, because the mean of its divisors is an integer number (62776011166).

Almost surely, 2125552022331 is an apocalyptic number.

125552022331 is a deficient number, since it is larger than the sum of its proper divisors (1).

125552022331 is an equidigital number, since it uses as much as digits as its factorization.

125552022331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 125552022331 its reverse (133220255521), we get a palindrome (258772277852).

The spelling of 125552022331 in words is "one hundred twenty-five billion, five hundred fifty-two million, twenty-two thousand, three hundred thirty-one".