Search a number
-
+
1255521132017 is a prime number
BaseRepresentation
bin10010010001010010111…
…001000001110111110001
311110000201102111211220022
4102101102321001313301
5131032301402211032
62400440051053225
7156464661352415
oct22212271016761
94400642454808
101255521132017
11444510a47369
121833b35a1215
139151a159b49
1444aa6212d45
15229d4126512
hex12452e41df1

1255521132017 has 2 divisors, whose sum is σ = 1255521132018. Its totient is φ = 1255521132016.

The previous prime is 1255521132011. The next prime is 1255521132059. The reversal of 1255521132017 is 7102311255521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1139447367601 + 116073764416 = 1067449^2 + 340696^2 .

It is a cyclic number.

It is not a de Polignac number, because 1255521132017 - 210 = 1255521130993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1255521132011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 627760566008 + 627760566009.

It is an arithmetic number, because the mean of its divisors is an integer number (627760566009).

Almost surely, 21255521132017 is an apocalyptic number.

It is an amenable number.

1255521132017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1255521132017 is an equidigital number, since it uses as much as digits as its factorization.

1255521132017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21000, while the sum is 35.

Adding to 1255521132017 its reverse (7102311255521), we get a palindrome (8357832387538).

The spelling of 1255521132017 in words is "one trillion, two hundred fifty-five billion, five hundred twenty-one million, one hundred thirty-two thousand, seventeen".