Base | Representation |
---|---|
bin | 10111011000101101… |
… | …10101010010011011 |
3 | 1012102000002111201211 |
4 | 23230112311102123 |
5 | 201203131434003 |
6 | 5433504323551 |
7 | 623063440360 |
oct | 135426652233 |
9 | 35360074654 |
10 | 12555343003 |
11 | 5363189035 |
12 | 25249135b7 |
13 | 1251225c58 |
14 | 87169c467 |
15 | 4d73bb96d |
hex | 2ec5b549b |
12555343003 has 32 divisors (see below), whose sum is σ = 14901004800. Its totient is φ = 10356353280.
The previous prime is 12555342991. The next prime is 12555343057. The reversal of 12555343003 is 30034355521.
It is not a de Polignac number, because 12555343003 - 225 = 12521788571 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12555343093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5874151 + ... + 5876287.
It is an arithmetic number, because the mean of its divisors is an integer number (465656400).
Almost surely, 212555343003 is an apocalyptic number.
12555343003 is a deficient number, since it is larger than the sum of its proper divisors (2345661797).
12555343003 is a wasteful number, since it uses less digits than its factorization.
12555343003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2467.
The product of its (nonzero) digits is 27000, while the sum is 31.
Adding to 12555343003 its reverse (30034355521), we get a palindrome (42589698524).
The spelling of 12555343003 in words is "twelve billion, five hundred fifty-five million, three hundred forty-three thousand, three".
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