Base | Representation |
---|---|
bin | 11100100011001010010100… |
… | …100100001101100110101110 |
3 | 121110120120100110020200201101 |
4 | 130203022110210031212232 |
5 | 112424200042002432032 |
6 | 1123014104243233314 |
7 | 35306344445060362 |
oct | 3443122444154656 |
9 | 543516313220641 |
10 | 125561566452142 |
11 | 3700a3a7973977 |
12 | 120ba80a67883a |
13 | 550a535786b32 |
14 | 23012d856d2a2 |
15 | e7b2279d1de7 |
hex | 72329490d9ae |
125561566452142 has 4 divisors (see below), whose sum is σ = 188342349678216. Its totient is φ = 62780783226070.
The previous prime is 125561566452121. The next prime is 125561566452151. The reversal of 125561566452142 is 241254665165521.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×1255615664521423 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31390391613034 + ... + 31390391613037.
It is an arithmetic number, because the mean of its divisors is an integer number (47085587419554).
Almost surely, 2125561566452142 is an apocalyptic number.
125561566452142 is a deficient number, since it is larger than the sum of its proper divisors (62780783226074).
125561566452142 is an equidigital number, since it uses as much as digits as its factorization.
125561566452142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62780783226073.
The product of its digits is 17280000, while the sum is 55.
The spelling of 125561566452142 in words is "one hundred twenty-five trillion, five hundred sixty-one billion, five hundred sixty-six million, four hundred fifty-two thousand, one hundred forty-two".
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