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12558711073 is a prime number
BaseRepresentation
bin10111011001000111…
…01011100100100001
31012102020102121212011
423230203223210201
5201210012223243
65434104432521
7623134165666
oct135443534441
935366377764
1012558711073
115365079567
122525a78741
131251b34cac
14871cd7a6d
154d783489d
hex2ec8eb921

12558711073 has 2 divisors, whose sum is σ = 12558711074. Its totient is φ = 12558711072.

The previous prime is 12558711047. The next prime is 12558711119. The reversal of 12558711073 is 37011785521.

12558711073 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6662314129 + 5896396944 = 81623^2 + 76788^2 .

It is an emirp because it is prime and its reverse (37011785521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12558711073 - 233 = 3968776481 is a prime.

It is a super-2 number, since 2×125587110732 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12558711023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6279355536 + 6279355537.

It is an arithmetic number, because the mean of its divisors is an integer number (6279355537).

Almost surely, 212558711073 is an apocalyptic number.

It is an amenable number.

12558711073 is a deficient number, since it is larger than the sum of its proper divisors (1).

12558711073 is an equidigital number, since it uses as much as digits as its factorization.

12558711073 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58800, while the sum is 40.

The spelling of 12558711073 in words is "twelve billion, five hundred fifty-eight million, seven hundred eleven thousand, seventy-three".