1256380941471 has 48 divisors (see below), whose sum is σ = 1907640956160. Its totient is φ = 730935878400.

The previous prime is 1256380941449. The next prime is 1256380941481. The reversal of 1256380941471 is 1741490836521.

It is not a de Polignac number, because 1256380941471 - 2¹³ = 1256380933279 is a prime.

It is a super-3 number, since 3×1256380941471³ (a number of 37 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (51).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1256380941421) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1847046 + ... + 2433996.

It is an arithmetic number, because the mean of its divisors is an integer number (39742519920).

It is a 1-persistent number, because it is pandigital, but 2⋅1256380941471 = 2512761882942 is not.

Almost surely, 2^{1256380941471} is an apocalyptic number.

1256380941471 is a deficient number, since it is larger than the sum of its proper divisors (651260014689).

1256380941471 is a wasteful number, since it uses less digits than its factorization.

1256380941471 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 587084 (or 587037 counting only the distinct ones).

The product of its (nonzero) digits is 1451520, while the sum is 51.

The spelling of 1256380941471 in words is "one trillion, two hundred fifty-six billion, three hundred eighty million, nine hundred forty-one thousand, four hundred seventy-one".