Search a number
-
+
12564500125 = 53293466069
BaseRepresentation
bin10111011001110011…
…10000111010011101
31012102122022201221111
423230321300322131
5201213003001000
65434432502021
7623234326462
oct135471607235
935378281844
1012564500125
115368372a01
1225279aa911
1312530b0c78
148729a3669
154d80c9cba
hex2ece70e9d

12564500125 has 16 divisors (see below), whose sum is σ = 16221207600. Its totient is φ = 9704990400.

The previous prime is 12564500107. The next prime is 12564500159. The reversal of 12564500125 is 52100546521.

It can be written as a sum of positive squares in 8 ways, for example, as 3645019876 + 8919480249 = 60374^2 + 94443^2 .

It is not a de Polignac number, because 12564500125 - 211 = 12564498077 is a prime.

It is a super-3 number, since 3×125645001253 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1729410 + ... + 1736659.

It is an arithmetic number, because the mean of its divisors is an integer number (1013825475).

Almost surely, 212564500125 is an apocalyptic number.

It is an amenable number.

12564500125 is a deficient number, since it is larger than the sum of its proper divisors (3656707475).

12564500125 is an equidigital number, since it uses as much as digits as its factorization.

12564500125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3466113 (or 3466103 counting only the distinct ones).

The product of its (nonzero) digits is 12000, while the sum is 31.

The spelling of 12564500125 in words is "twelve billion, five hundred sixty-four million, five hundred thousand, one hundred twenty-five".

Divisors: 1 5 25 29 125 145 725 3625 3466069 17330345 86651725 100516001 433258625 502580005 2512900025 12564500125