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12565433 is a prime number
BaseRepresentation
bin101111111011…
…101110111001
3212122101112102
4233323232321
511204043213
61125153145
7211542626
oct57735671
925571472
1012565433
117102661
12425b7b5
1327ac48a
14195134d
151183158
hexbfbbb9

12565433 has 2 divisors, whose sum is σ = 12565434. Its totient is φ = 12565432.

The previous prime is 12565409. The next prime is 12565463. The reversal of 12565433 is 33456521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9168784 + 3396649 = 3028^2 + 1843^2 .

It is a cyclic number.

It is not a de Polignac number, because 12565433 - 28 = 12565177 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12565396 and 12565405.

It is not a weakly prime, because it can be changed into another prime (12565463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6282716 + 6282717.

It is an arithmetic number, because the mean of its divisors is an integer number (6282717).

Almost surely, 212565433 is an apocalyptic number.

It is an amenable number.

12565433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12565433 is an equidigital number, since it uses as much as digits as its factorization.

12565433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10800, while the sum is 29.

The square root of 12565433 is about 3544.7754512804. The cubic root of 12565433 is about 232.4836879140.

The spelling of 12565433 in words is "twelve million, five hundred sixty-five thousand, four hundred thirty-three".