Base | Representation |
---|---|
bin | 10111011010010010… |
… | …01111011110001111 |
3 | 1012102220221212112222 |
4 | 23231021033132033 |
5 | 201220022314310 |
6 | 5435055445555 |
7 | 623313655436 |
oct | 135511173617 |
9 | 35386855488 |
10 | 12568557455 |
11 | 536a694273 |
12 | 25292268bb |
13 | 1253ba195c |
14 | 87333c11d |
15 | 4d862c055 |
hex | 2ed24f78f |
12568557455 has 4 divisors (see below), whose sum is σ = 15082268952. Its totient is φ = 10054845960.
The previous prime is 12568557451. The next prime is 12568557479. The reversal of 12568557455 is 55475586521.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55475586521 = 139 ⋅399104939.
It is not a de Polignac number, because 12568557455 - 22 = 12568557451 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12568557397 and 12568557406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12568557451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1256855741 + ... + 1256855750.
It is an arithmetic number, because the mean of its divisors is an integer number (3770567238).
Almost surely, 212568557455 is an apocalyptic number.
12568557455 is a deficient number, since it is larger than the sum of its proper divisors (2513711497).
12568557455 is an equidigital number, since it uses as much as digits as its factorization.
12568557455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2513711496.
The product of its digits is 8400000, while the sum is 53.
The spelling of 12568557455 in words is "twelve billion, five hundred sixty-eight million, five hundred fifty-seven thousand, four hundred fifty-five".
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