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12602135041 = 107117776963
BaseRepresentation
bin10111011110010010…
…10101001000000001
31012112021010210100021
423233021111020001
5201302121310131
65442255253441
7624202244326
oct135711251001
935467123307
1012602135041
115387638641
12253851a281
13125ab2a152
1487799cb4d
154db560e11
hex2ef255201

12602135041 has 4 divisors (see below), whose sum is σ = 12719912112. Its totient is φ = 12484357972.

The previous prime is 12602135033. The next prime is 12602135057. The reversal of 12602135041 is 14053120621.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12602135041 - 23 = 12602135033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12602134997 and 12602135015.

It is not an unprimeable number, because it can be changed into a prime (12602135011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58888375 + ... + 58888588.

It is an arithmetic number, because the mean of its divisors is an integer number (3179978028).

Almost surely, 212602135041 is an apocalyptic number.

It is an amenable number.

12602135041 is a deficient number, since it is larger than the sum of its proper divisors (117777071).

12602135041 is a wasteful number, since it uses less digits than its factorization.

12602135041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 117777070.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 12602135041 its reverse (14053120621), we get a palindrome (26655255662).

The spelling of 12602135041 in words is "twelve billion, six hundred two million, one hundred thirty-five thousand, forty-one".

Divisors: 1 107 117776963 12602135041