Search a number
-
+
12612313401131 is a prime number
BaseRepresentation
bin1011011110001000100001…
…1101011100011100101011
31122122201120210202202011102
42313202020131130130223
53123120004212314011
642454003343152015
72441131612030133
oct267421035343453
948581523682142
1012612313401131
114022941126974
1214b84262a560b
1370644a3c2362
14318621341ac3
1516d11dcb873b
hexb788875c72b

12612313401131 has 2 divisors, whose sum is σ = 12612313401132. Its totient is φ = 12612313401130.

The previous prime is 12612313401109. The next prime is 12612313401143. The reversal of 12612313401131 is 13110431321621.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12612313401131 is a prime.

It is a super-2 number, since 2×126123134011312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12612313401094 and 12612313401103.

It is not a weakly prime, because it can be changed into another prime (12612313401161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6306156700565 + 6306156700566.

It is an arithmetic number, because the mean of its divisors is an integer number (6306156700566).

Almost surely, 212612313401131 is an apocalyptic number.

12612313401131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12612313401131 is an equidigital number, since it uses as much as digits as its factorization.

12612313401131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

Adding to 12612313401131 its reverse (13110431321621), we get a palindrome (25722744722752).

The spelling of 12612313401131 in words is "twelve trillion, six hundred twelve billion, three hundred thirteen million, four hundred one thousand, one hundred thirty-one".